Алгебра: Log(3) (x^3-x)-log(3) x=log(3) 3

$log_3(x^3-x)-log_3x=log_33$
ОДЗ: {x³-x>0 {x(x²-1)>0 {x(x-1)(x+1)>0
{x>0 => {x>0 => {x>0
- + - +
__________-1____________0____________1__________
_______________________ 0 ///////////////////////////////////////
ОДЗ: x∈(0;+∞)

$log_3 \frac{x^3-x}{x}=log_33\\\\ \frac{x(x^2-1)}{x}=3\\\\x^2-1=3\\\\x^2=4\\\\x=б2\; \; \; x\ \textgreater \ 0\\\\x=2$

Ответ: 2