16(x-1)(x+1)-(4x-7)²=0

Question

16(x-1)(x+1)-(4x-7)²=0

Answer 1

16(х^2-1)-(16х^2-56х+49)=0
16х^2-16-16х^2+56х-49=0
56х=49+16
56х=65
х=65:56
х=1,16

Comments

Спасибо))