Решите уравнение : sin^4 4x-cos^4 4x-sin4x=2sin²4x

Question

Решите уравнение : sin^4 4x-cos^4 4x-sin4x=2sin²4x

Answer 1

Sin(4x)^4 - cos(4x)^4 = (cos(4x)^2 - sin(4x)^2)*(sin(4x)^2 + cos(4x)^2) = (sin(4x)^2 - cos(4x)^2)*1
-cos(4x)^2 = -1 + sin(4x)^2
sin(4x) = -1
x = (-1)^(m+1) *p/8 + p*m/4