Алгебра: (11x+5)(2x-3)+(12-8x) вынести общий множитель за скобки (3a+1)(7a-2)-(6a+2)(8a+3)

$(11x+5)(2x-3)+(12-8x)=\\= (11x+5)(2x-3)+((-4)*(-3)+(-4)*2x)=\\= (11x+5)(2x-3)+(-4)*((-3)+2x)=\\= (11x+5)*(2x-3)+(-4)*(2x-3)=\\= (2x-3)*((11x+5)+(-4))=(2x-3)(11x+1)$
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$(3a+1)(7a-2)-(6a+2)(8a+3)=\\= (3a+1)(7a-2)-(2*3a+2*1)(8a+3)=\\= (3a+1)(7a-2)-2*(3a+1)(8a+3)=\\= (3a+1)*(7a-2)-(3a+1)*(2*(8a+3))=\\= (3a+1)*((7a-2)-(2*(8a+3)))=\\= (3a+1)*(7a-2-2*(8a+3))=\\= (3a+1)*(7a-2-16a-6)=(3a+1)*(-9a-7)=\\= (3a+1)*((-1)*9a+(-1)*7)=\\= (3a+1)*(-1)*(9a+7)=(-1)*(3a+1)*(9a+7)=\\= -(3a+1)(9a+7)$