Алгебра: Решите пожалуйста №1,2,3,5

Y^4/y*(y^2)^3=y^(4-1+2*3)=y^9
5x^2y-8x^2y+x^2y=x^2y*(5-8+1)=-2x^2y
(2ab^2)^4*(2a^2b)^3=2^7*a^10*b^11
(m^4)^7/((m^3)^9*m) = m ^ (4*7-3*9-1) = 1
2)
(2^5)^2*3^10/6^7 =2^10*3^10 / 6^7 = 6^10 / 6^7 = 6^3 = 216
3)
(3/5)^3*(5/3)^2 и 1,6^0
(3/5)^1 и 1
3/5 < 1
5)
(2x^3)^5(2x^2)^4 / (4x^5)^4 = 54
2^(5+4-2*4)*x^(3*5+2*4-5*4) = 54
2^(1)*x^(3) = 54
2*x^(3) = 54
x^(3) = 27
x=3