Алгебра: (х + 2)(х - 3) - (2х - 5)(х + 3) = х(х

Решите задачу:

$(x + 2)(x - 3) - (2x - 5)(x + 3) = x(x - 5) \\ {x}^{2} + 2x - 3x - 6 - ( {2x}^{2} - 5x + 6x - 15) = {x }^{2} - 5x \\ {x}^{2} - x - 6 - {2x}^{2} + 5x - 6x + 15 = {x}^{2} - 5x \\ {x}^{2} - {x}^{2} - x + 5x - 6x + 5x - 6 + 15 = 0 \\ 3x + 9 = 0 \\ 3x = - 9 \\ x = - 9 \div 3 \\ x = - 3$

(х + 2)(х - 3) - (2х - 5)(х + 3) = х(х - 5)