Алгебра: Помогитеее)))пожалуйста)))

1)
а)
$\sqrt{121}=\sqrt{11^2}=11$
$\sqrt{1.44}=\sqrt{1.2^2}=1.2\\\sqrt{\frac{16}{225}}=\sqrt{\frac{4^2}{15^2}}=\frac{4}{15}\\\sqrt{1\frac{25}{144}}=\sqrt{\frac{169}{144}}=\sqrt{\frac{13^2}{12^2}}=\frac{13}{12}$

б)
$(\sqrt{3})^2=3\\(-\sqrt{13})^2=(-1)^2*(\sqrt{13})^2=1*13=13\\(\sqrt{5})^4=5^2=25$

в)
$(3\sqrt{5})^2=3^2*5=9*5=45\\-3*\sqrt{(-5)^2}=-3*\sqrt{5^2}=-3*5=-15\\(-3\sqrt{5})^4=(-3)^4*(5)^2=81*25=2025$

г)
$\sqrt{729}-\sqrt{529}=\sqrt{27^2}-\sqrt{23^2}=27-23=4\\\sqrt{\frac{1}{9}}*\sqrt{0.36}=\sqrt{\frac{1^2}{3^2}}*\sqrt{0.6^2}=\frac{1}{3}*0.6=0.2$

2)
a)
$x^2=121\\\sqrt{x^2}=\sqrt{121}\\|x|=11\\x=11\ \ \ \ \ x=-11$

б)
$x^2=11\\\sqrt{x^2}=\sqrt{11}\\|x|=\sqrt{11}\\x=\sqrt{11}\ \ \ \ \ \ x=-\sqrt{11}$

в)
$\sqrt{x}=11\\(\sqrt{x})^2=11^2\\x=121$